Pratit Luthra 4 years, 6 months ago sec 2 x=22tanx 1tan 2 x=22tanx tan 2 x2tanx1=0 (tanx1) 2 =0 tanx=1 1 Thank You ANSWER Class12th practical Shivam Mishra, Meritnation Expert added an answer, on 26/7/16 Shivam Mishra answered this Dear Student, Please find below the solution to the asked query We have f 2 tanx 1 tan 2 x = cos 2 x 1 sec 2 x 2 tanx 2 = cos 2 x 1 2 1 cos 2 x 2 sinx cosx = cos 2 x 1 2 1 2 sinx cosx cos 2 x = cos 2 x 1 2 1 sin 2 x cos 2 x = 2 cos 2 x 1 1 2 1 sin 2 x cos 2 x = 2 cos 2 x 2 1 sin 2 x cos 2 x f 2 tanx 1 tan 2 x = 1 sin 2 x We know that 2 tanx 1 tan 2 x = sin 2 x f sin 2Sin2xcos2x = 1 tan2x1 = sec2x sin 2x = 2 sin x cos x cos 2x = 2 cos2x 1 tan x = sin x cos x sec x = 1 cos x cot x = cos x sin x csc x = 1 sin x Some integration formulas R xn dx = xn1 n1 C R 1 x dx = lnjxjC R ex dx = ex C R sin x dx = cos x C R cos x dx = sin xC R
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