Pratit Luthra 4 years, 6 months ago sec 2 x=22tanx 1tan 2 x=22tanx tan 2 x2tanx1=0 (tanx1) 2 =0 tanx=1 1 Thank You ANSWER Class12th practical Shivam Mishra, Meritnation Expert added an answer, on 26/7/16 Shivam Mishra answered this Dear Student, Please find below the solution to the asked query We have f 2 tanx 1 tan 2 x = cos 2 x 1 sec 2 x 2 tanx 2 = cos 2 x 1 2 1 cos 2 x 2 sinx cosx = cos 2 x 1 2 1 2 sinx cosx cos 2 x = cos 2 x 1 2 1 sin 2 x cos 2 x = 2 cos 2 x 1 1 2 1 sin 2 x cos 2 x = 2 cos 2 x 2 1 sin 2 x cos 2 x f 2 tanx 1 tan 2 x = 1 sin 2 x We know that 2 tanx 1 tan 2 x = sin 2 x f sin 2Sin2xcos2x = 1 tan2x1 = sec2x sin 2x = 2 sin x cos x cos 2x = 2 cos2x 1 tan x = sin x cos x sec x = 1 cos x cot x = cos x sin x csc x = 1 sin x Some integration formulas R xn dx = xn1 n1 C R 1 x dx = lnjxjC R ex dx = ex C R sin x dx = cos x C R cos x dx = sin xC R
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F(2tanx/1 tan^2x)=(cos2x 1)(sec^2x 2tanx)/2 then f(1)
F(2tanx/1 tan^2x)=(cos2x 1)(sec^2x 2tanx)/2 then f(1)-In any triangle we have 1 The sine law sin A / a = sin B / b = sin C / c 2 The cosine laws a 2 = b 2 c 2 2 b c cos A b 2 = a 2 c 2 2 a c cos B c 2 = a 2 b 2 2 a b cos C Relations Between Trigonometric FunctionsQuestion Prove The Identity Sec^2/2 Tan X = Csc 2x This problem has been solved!
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Click here👆to get an answer to your question ️ Match the statements of Column I with values of Column II Column IColumn IIAIf f(x) = x 1 , when x2 tan^2x = 1 tan^2 x x = pi/6 {x is angle expressed in radians} General solution is x = 2* n * pi pi/6 (where n is a natural number) (tan x)× (tan 2x) = 1 or tan x = 1/ (tan 2x) =cot 2x or tan x = tan (pi/2 2x) or x = npi (pi/2–2x) or x2x= (n1/2)pi Misc 1 Misc 2 Important Misc 3 Deleted for CBSE Board 22 Exams Misc 4 Important Deleted for CBSE Board 22 Exams Misc 5 Deleted for CBSE Board 22 Exams Misc 6 Deleted for CBSE Board 22 Exams
Simply tan (AB) = tanAtanB/1tanAtanB From this formula we can derive tan (2x) as tan (xx) So tan (2x)= 2tanx/1tanxtanx We can always go forGet an answer for 'Prove the following sin 2x = (tan x)(1 cos 2x)' and find homework help for other Math questions at eNotes∫ d x cos 2 x = tan x C 2 and by combining the two constants of integration into one, we find the answer (1) ∫ ( 1 tan x) 2 d x = tan x − 2 log cos
Solve for x tan (2x)=1 tan (2x) = 1 tan ( 2 x) = 1 Take the inverse tangent of both sides of the equation to extract x x from inside the tangent 2x = arctan(1) 2 x = arctan ( 1) The exact value of arctan(1) arctan ( 1) is π 4 π 4 2x = π 4 2 x = π 4 Divide each term by 2 2Solve the equation √3 sin2x cos2x = 0 for π≤x≤π No idea how to approach this one Thanks a if sinx=7/5 and angle x is in quadrant 2 and cos y=12/13 and angle y is in quadrant 1 find sin (xy) asked in TRIGONOMETRY by harvy0496 Apprentice doubleangle
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Rewrite sec(x) sec ( x) in terms of sines and cosines Rewrite tan(x) tan ( x) in terms of sines and cosines Multiply by the reciprocal of the fraction to divide by 1 cos(x) 1 cos ( x) Write cos(x) cos ( x) as a fraction with denominator 1 1 Cancel the common factor of cos(x) cos ( x) Explanation 2tanx 1 tan2x = 2 sinx cosx sec2x = 2 sinx cosx 1 cos2x = 2sinx cosx × cos2x 1 = 2sinxcosx Best answer We have f (2tanx/ (1 tan2x)) = 1/2 (1 cos2x) (sec2x tanx) = 1/2x 2cos2x x (1 tan2x 2tanx) = cos2x x (1 tanx)2 = {cosx x (1 tanx)}2 = (cosx sinx)2 = 1 sin (2x) Thus, f (sin 2x) = 1 sin (2x)
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Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack ExchangeCos2 (x) (1 tan2 (x)) = 1 cos 2 ( x) ( 1 tan 2 ( x)) = 1 Replace the cos2(x) cos 2 ( x) with 1−sin2 (x) 1 sin 2 ( x) based on the sin2(x)cos2(x) = 1 sin 2 ( x) cos 2 ( x) = 1 identity 1−sin2 (x)(1tan2(x)) = 1 1 sin 2 ( x) ( 1 tan 2 ( x)) = 1 Simplify each term Tap for more stepsSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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You can put this solution on YOUR website! Solve the equation 2cos2x = √3 for 0°≤x≤360° I did this cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?Answer (1 of 4) In Trigonemetry Laws and Identities, there are some rule that we will use to prove 1 / sec² (x) = cos² (x) * tan² (x) 1 = sec² (x) * sin² (x) cos² (x) = 1 * tan (x) = sin (x) / cos (x) We will prove from the Left Hand Side We know that sec² (x) = tan² (x) 1, so 1 /
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Trigonometry Solve for x tan (2x)= (2tan (x))/ (1tan (x)^2) tan(2x) = 2tan(x) 1−tan2 (x) tan ( 2 x) = 2 tan ( x) 1 tan 2 ( x) Since x x is on the right side of the equation, switch the sides so it is on the left side of the equation 2tan(x) 1− tan2(x) = tan(2x) 2 tan ( x) 1 tan 2 ( x) = tan ( 2 x)Sin(2x) = (2tan(x)) / (1tan^2(x)) *** Start with RHS 2tanx/(1tan^2x) 2tanx/(sec^2x) 2(sinx/cosx)/(1The equation `sec^2x 2*tan x = 4` has to be solved for x Using the basic identity `sin^2x cos^2x = 1` , it is possible to express sec x in terms of tan x
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If F 2tanx 1 Tan 2x Cos2x 1 Sec 2x Tanx 2 Then F X bestpictjcry Tan 2x Tan 2x Ex 3 4 8 Find General Solution Of Sec 2 2x 1 Tan 2x Teachoo Example 14 Show Tan 3x Tan 2x Tan X Tan 3x Tan 2x Tan X Find The Range Of F X Sqrt 4 Sqrt 1 Tan 2x 3 Ex 3 3 23 Prove Tan 4x 4 Tan X 1 Tan2 X 1 6tan2xWhy create a profile on Shaalaacom? Ex 34, 8 Find the general solution of the equation sec2 2x = 1 – tan 2x sec2 2x = 1 – tan 2x 1 tan2 2x = 1 – tan2x tan2 2x tan2x = 1 – 1 tan2 2x tan2x = 0 tan 2x (tan2x 1) = 0 Hence We know that sec2 x = 1 tan2 x So, sec2 2x = 1 tan2 2x tan 2x = 0 ta
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`f((2tanx)/(1tan^2x))=((cos2x1)(sec^2x2tanx))/2` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in examsAnswer (1 of 7) Here, tan x = 1/2 We know that, the relation between tan x and sec x is sec^2xtan^2x=1 Using this relation, first, we will determine the value of cos x and then, we will determine the value of sin x So now, sec^2xtan^2x=1 => sec^2x(1/4)=1 => sec^2x=1(1/4) => sec^2x=Weekly Subscription $249 USD per week until cancelled Monthly Subscription $799 USD per month until cancelled Annual Subscription $3499 USD per year until cancelled
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If tan x = 2, then y / x = 2 / 1 Then, using, √(x 2 y 2) = r √(2 2 1 2) = √5 = r So sin x = y/r = 2/√5 And using cos 2x = 1 2(sin x) 2 cos 2x = 1 2(2/√5) 2 cos 2x = 1 2 (4/5)Sec(x)^22=tan(x)^2 Replace the with based on the identity Subtract from Move all terms containing to the left side of the equation Tap for more steps Subtract from both sides of the equation Simplify the left side of the equation Tap for more steps Rewrite as Factor out ofThe first derivative of the trigonometric function of tangent with respect to its argument is the reciprocal of the trigonometric function of cosine squared Snarf!
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2tanx/(1tan^2x) sin^2x= =(1cos(2x))/2 (1cos(2x))/2 0 I have two problems I am stuck on, if you could show me how to solve the problems it would be much appreciated 1) Find sin 2x, cos 2x, and tan 2x from the given information tan x = − 1/6, cos x > 0 sin 2x = cos 2x = tan 2x = Math Prove the identity sec^4x tan^4x = 12tan^2x calculus Let F(x)= the integral from 0 to 2x of tan(t^2) dt Use your calculator to find F″(1) By applying the fundamental theorem of calculus, I got the derivative of the integral (F'(x)) to be 2tan(2x^2) When I
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I just want to ask The equation says tan2x=2tanx/1tan^2x How did it become 2tanx and 1tan^2x?I need to use the fact that $\tan 2x=\sin2x \ /\cos2x$ to prove that $$\tan 2x=\frac{2\tan x}{1\tan^2x}$$ I don't know where to start Please help or hint Thanks in advance sec=4 find sin(2x), cos(2x), tan(2x) These problems seem straight forward but I keep getting the wrong answer If you could please in detail show me how to solve this I would really, really, really appreciate it so I don't throw my Trig book out the window
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Evaluate $\displaystyle \large \lim_{x \,\to\, \tan^{1}{3}} \normalsize {\dfrac{\tan^2{x}2\tan{x}3}{\tan^2{x}4\tan{x}3}}$ Get an answer for 'verify (1 tan^2x)/(tan^2x) = csc^2x' and find homework help for other Math questions at eNotes1 Your solution is not very rigorous after 0 = t a n 2 x 2 t a n x − 1 After that line, the equation should be t a n x = − 2 ± 2 2 − 4 ( 1) ( − 1) 2 ( 1) Also, after that, it's t a n x = 2 − 1 ≈ or t a n x = 2 1 ≈ Then, x = t a n − 1 ( ) ≈ 225, 25 Share edited May 7 '14 at 1125 answered May
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Trigonometry 1Solve tan^2x tan x – 1 = 0 for the principal value (s) to two decimal places 6Prove that tan y cos^2 y sin^2y/sin y = cos y sin u0004y 10Prove that 1tanθ/1tanθ = sec^2θ2tanθ/1tan^2θ 17Prove that sin^2wcos^2w/tan w sin w cos w tan w = The limit of multiplication of the functions can be split as product of their limits as per the product rule of limits = ( lim x → 0 2 1 − tan 2 x) × ( lim x → 0 x tan 3 x ( 1 − cos 2 x) 2) Now, find the limit of the first factor by the direct substitution but do1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials information
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See the answer Show transcribed image text Expert Answer 100% (3 ratings) Previous question Next question Transcribed Image Text from this Question Prove the identity sec^2/2 tan x = csc 2xI am unable to see why $$1 \tan^2 x= 1/\cos^2x$$ I have looked into the topic anad I am familiar with the reciprocal ratios of cosec, sec, and cot but cannot derive how this statement makes sense Any help on the topic would be very much appreciated Use trig identities 1 tan^2 x = 1/cos^2 x = sec^2 x (1 tan x) = 1 tan^2 x 2tan x = sec^2 x 2tan x
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(1tan^2x)/(1tan^2(x)) 1 = 2cos^2(x) The trigonometric equation is sec 2 (x) tan x = 2tan(x) tan x sec 2 (x) 2 = 0 ⇒tan x = 0 and sec 2 (x) 2 = 0 tan x = 0 tan x = tan 0 The genaral solution of tan(θ) = tan(α) is θ = nπ α, where n is an integer ⇒ x = nπ 0 x = nπn = 0,1,2 sec 2 (x) 2 = 0 sec 2 (x) = 2 Using reciprocal identity sec 2 x = 1/cosProve as an identity;
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